本文共 4328 字,大约阅读时间需要 14 分钟。
请你设计一个数据结构,支持 添加新单词 和 查找字符串是否与任何先前添加的字符串匹配 。
实现词典类 WordDictionary :
WordDictionary() 初始化词典对象
void addWord(word) 将 word 添加到数据结构中,之后可以对它进行匹配 bool search(word) 如果数据结构中存在字符串与 word 匹配,则返回 true ;否则,返回 false 。word 中可能包含一些 ‘.’ ,每个 . 都可以表示任何一个字母。示例:
输入: [“WordDictionary”,“addWord”,“addWord”,“addWord”,“search”,“search”,“search”,“search”] [[],[“bad”],[“dad”],[“mad”],[“pad”],[“bad”],[".ad"],[“b…”]] 输出: [null,null,null,null,false,true,true,true]解释:
WordDictionary wordDictionary = new WordDictionary(); wordDictionary.addWord(“bad”); wordDictionary.addWord(“dad”); wordDictionary.addWord(“mad”); wordDictionary.search(“pad”); // return False wordDictionary.search(“bad”); // return True wordDictionary.search(".ad"); // return True wordDictionary.search(“b…”); // return True提示:
1 <= word.length <= 500 addWord 中的 word 由小写英文字母组成 search 中的 word 由 ‘.’ 或小写英文字母组成 最调用多 50000 次 addWord 和 search来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/design-add-and-search-words-data-structure 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
class WordDictionary { class TrieNode { public: bool isEnd; unordered_mapnext; TrieNode() { isEnd = false; next.clear(); } };public: TrieNode * root; /** Initialize your data structure here. */ WordDictionary() { root = new TrieNode(); } /** Adds a word into the data structure. */ void addWord(string word) { TrieNode* cur = root; for (char c: word) { if (cur->next.count(c) == 0) { cur->next[c] = new TrieNode(); } cur = cur->next[c]; } cur->isEnd = true; } /** Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter. */ bool search(string word) { return find(word, 0, word.length(), root); } bool find(string& word, int start, int end, TrieNode* cur) { if (start == end) { return cur->isEnd; } if (word[start] != '.') { if (cur->next.count(word[start]) == 0) { return false; } return find(word, start+1, end, cur->next[word[start]]); } else { for (auto iter: cur->next) { bool flag = find(word, start+1, end, cur->next[iter.first]); if (flag) { return true; } } return false; } return false; }};/** * Your WordDictionary object will be instantiated and called as such: * WordDictionary* obj = new WordDictionary(); * obj->addWord(word); * bool param_2 = obj->search(word); */
前缀树的定义合并到类中。
class WordDictionary { bool isEnd; unordered_mapnext;public: /** Initialize your data structure here. */ WordDictionary() { isEnd = false; } /** Adds a word into the data structure. */ void addWord(string word) { WordDictionary* cur = this; for (char c: word) { if (cur->next.count(c) == 0) { cur->next[c] = new WordDictionary(); } cur = cur->next[c]; } cur->isEnd = true; } /** Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter. */ bool search(string word) { return find(word, 0, word.length(), this); } bool find(string& word, int start, int end, WordDictionary* cur) { if (start == end) { return cur->isEnd; } if (word[start] != '.') { if (cur->next.count(word[start]) == 0) { return false; } return find(word, start+1, end, cur->next[word[start]]); } else { for (auto iter: cur->next) { bool flag = find(word, start+1, end, cur->next[iter.first]); if (flag) { return true; } } return false; } return false; }};/** * Your WordDictionary object will be instantiated and called as such: * WordDictionary* obj = new WordDictionary(); * obj->addWord(word); * bool param_2 = obj->search(word); */